Question

A 2 L bottle containing only air is sealed at a temperature of 22°C and a pressure of 0.982 atm. The bottle is placed in a freezer and allowed to cool to -3°C. What is the pressure in the bottle if the volume changes to 1.8 L?

Answer 1

Answer:

.997 atm

Explanation:

1. Find the combined gas law formula...

(P1V1/T1 = P2V2/T2)

2. Find our numbers...

P1= .982 atm

P2= ? (trying to find)

V1= 2 L

V2= 1.8 L

T1= 22 C = 295 K

T2= -3 C = 270 K

- Note: always use Kelvin. To find Kelving add 273 to ___C.

3. Rearrange formula to fit problem...

(P2=P1V1T2/V2T1)

4. Fill in our values...

P2= .982 atm x 2 L x 270 K / 1.8 L x 295 K

5. Do the math and your answer should be...

.997 atm

- If you need more help or still do not understand please let me know and I would be glad to help!