Question

A certain quantity grows exponentially over time. The initial quantity at t = 0 is 100. The quantity grows by a factor of 2.5%. What is the quantity at t = 5?

Answer 1

So the quantity of the growth is C.113.1408. I hope you are satisfied with my answer and feel fee to ask for more if you have clarification and further question. Have a nice day

Answer 2

Answer:

quantity after 5 years will be 113.14

Step-by-step explanation:

A certain quantity grows exponentially over time.

and the function will represent the growth will be $f(t)=ar^{t}$

where a = 100

and growth factor is 2.5%

So the common factor by which the growth will be = 1 + 0.025 = 1.025

$f(t)=100(1.025)^{t}$

After   t = 5 years

f(5) = 100 (1.025)⁵

     = 100 (1.1314)

      = 113.14

Therefore, quantity after 5 years will be 113.14.