Question

Solve 2x^2-3x-5 using the quadratic formula

Answer 1

Answer:

$2 {x}^{2} - 3x - 5 \\ 2 {x}^{2} - 5x + 2x - 5 \\ 2 {x}^{2} + 2x - 5x - 5 \\ 2x(x + 1) - 5(x + 1) \\ = (2x - 5)(x + 1)$

$2x - 5 = 0 \\ 2x = 0 + 5 \\ \frac{2x}{2} = \frac{5}{2} \\ x = \frac{5}{2}$

$x + 1 = 0 \\ x = - 1$

hope this helps you.....!