Use the polynomial remainder theorem. It says a polynomial [tex]p(x)[/tex] is divisible by [tex]x-c[/tex] if [tex]p(c)=0[/tex].
We have [tex]p(x)=2x^5+3x^4+25x^2-1[/tex], and
[tex]p(-3)=2(-3)^5+3(-3)^4+25(-3)^2-1=-19\neq0[/tex]
So [tex]x+3[/tex] is NOT a factor, and the answer is False.
Answer:
False
Step-by-step explanation:
If x + 3 is a factor, x = -3 should be a root
2(-3)⁵ + 3(-3)⁴ + 25(-3)² - 1
-19
Since the remainder is non-zero, -3 is not a root.
Hence x+3 is not a factor