Question

If 468mL of gas is measured at 0.83atm, then what volume would the gas occupy at 1.05atm?

Answer 1

Answer: V= 369.94mL

Explanation:

Applying Boyle's law

P1V1=P2V2

P1= 0.83atm, V1= 468mL , P2 = 1.08atm V2= ?

Substitute into above

0.83× 468= 1.08× V2

V2 = 369.9mL