Respuesta :
According to the law of indices[tex]a^{-\frac{1}{n} }=\dfrac{1}{\sqrt[n]{a} }[/tex]. The resulting value of the indices expression is 1/6
Negative exponents
According to the law of indices as shown below
[tex]a^{-\frac{1}{n} }=\dfrac{1}{\sqrt[n]{a} }[/tex]
Given the indices expression
[tex]36^{-\dfrac{1}{2} }[/tex]
Applying the law of indices above:
[tex]36^{-\frac{1}{2} }=\frac{1}{\sqrt{36} }[/tex]
Since the square root of 36 is equivalent to 6, hence;
[tex]36^{-\frac{1}{2} }=\frac{1}{\sqrt{36} }=\frac{1}{6}[/tex]
Hence the resulting value of the indices expression is 1/6
Learn more on indices here: https://brainly.com/question/10339517
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