1) The slope of the point (0,0) and (2,1) is 1/2.
2) The slope of the point (0,-1) and (2,-5) is -2.
3) The slope of the point (0,7) and (2,4) is -3/2.
4) The points (-1,3) and (-1,-3) has No slope.
5) The slope of the point (1,-3) and (-1,-3) is zero.
Step-by-step explanation:
There are five set of points given in the question.
You need to find out the slope of the line formed by the points.
The formula used to find the slope of a line is given by,
Slope = [tex]\frac{y2-y1}{x2-x1}[/tex]
1) The given points are (0,0) and (2,1)
(x1,y1) ⇒ (0,0)
(x2,y2) ⇒ (2,1)
Slope = [tex]\frac{1-0}{2-0}[/tex]
⇒ 1/2 is the slope.
2) The given points are (0,-1) and (2,-5)
(x1,y1) ⇒ (0,-1)
(x2,y2) ⇒ (2,-5)
Slope = [tex]\frac{-5+1}{2-0}[/tex]
⇒ [tex]\frac{-4}{2}[/tex]
⇒ -2 is the slope.
3) The given points are (0,7) and (2,4)
(x1,y1) ⇒ (0,7)
(x2,y2) ⇒ (2,4)
Slope = [tex]\frac{4-7}{2-0}[/tex]
⇒ -3/2 is the slope.
4) The given points are (-1,3) and (-1,-3)
(x1,y1) ⇒ (-1,3)
(x2,y2) ⇒ (-1,-3)
Slope = [tex]\frac{-3-3}{-1+1}[/tex]
⇒ -6/0 (No slope)
If the denominator of a fraction is zero, the expression is not a legal fraction because it's overall value is undefined.
∴ There is no slope.
5) The given points are (1,-3) and (-1,-3)
(x1,y1) ⇒ (1,-3)
(x2,y2) ⇒ (-1,-3)
Slope = [tex]\frac{-3+3}{-1-1}[/tex]
⇒ 0/-2
∴ The slope is zero.
