Question

A company has found that the daily demand x for its boxes of chocolates is inversely proportional to the price p. When the price is $5, the demand is 800 boxes. Approximate the demand when the price is increased to $6.

Answer 1

The demand is 667 when the price is $6.

Step-by-step explanation:

Given,

The demand of x box of chocolates is inversely proportional to the price p.

So, x∝$\frac{1}{p}$

or, x = k.$\frac{1}{p}$ where, k is any constant

Again, when the price is $5, demand is 800 boxes.

To find the the demand when the price is increase to $6.

Now,

Taking p=5 and x= 800 we get,

800 = k.$\frac{1}{5}$

or, k = 800×5 = 4000

Now,

Taking p=6 and k=4000 we get,

x = 4000×$\frac{1}{6}$ = 666.67 (approx)

Hence,

The demand is 667 when the price is $6.