Question

How many moles are present in 45.0 g of lithium oxide (Li2O)?

Answer 1

Molar mass Li2O = 7.0 x 2 + 16 => 30 g/mol

1 mole Li2O ---------- 30 g
( moles Li2O ) -------- 45.0 g

moles Li2O = 45.0 x 1 / 30

moles Li2O = 45.0 / 30

= 1.50 moles of Li2O 

hope this helps!

Answer 2

1.5 moles are present in 45.0 g of lithium oxide.

What is Mole ?

Mole is a fundamental unit which measures the amount of substance.

How to calculate the number of moles ?

To calculate the number of mole simply divide the given weight of a sample by its molecular weight.

Number of moles = $\frac{\text{Given mass}}{\text{Molar mass}}$

First we have to calculate the molar mass.

Molar mass of Li₂O = 2 × (Atomic weight of Lithium) + Atomic weight of Oxygen

                                = 2 × (7) + 16

                                = 14 + 16

                                = 30 g/mol

Now put the value in above formula we get

Number of moles = $\frac{\text{Given mass}}{\text{Molar mass}}$

                             = $\frac{45.0\ g}{30\ g/mol}$

                             = 1.5 mol

Thus, from  above conclusion we can say that 1.5 moles are present in 45.0 g of lithium oxide.

Learn more about the Number of moles here: https://brainly.com/question/13314627

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