The magnitude of the force is F=1.68×10 ^20 N
Explanation:
Given data
q1 =1.5 10 ^6 q2=3.2 10^6 r=1.5
We have the formula
By the coulomb's law
F= K. q1 ×q2 / r²
The K value is given by
8.99 10^9 Nm²/ c²
substitute the values we get,
F= ( 8.99× 10^9 Nm²/ c²) ×(1.5 ×10 ^6)×(3.2 ×10 ^6)/ (1.6 m² )
F=1.68×10 ^20 N
The magnitude of the force is F=1.68×10 ^20 N
