contestada

2. What is the magnitude of the force a 1.5 C charge exerts on a 3.2 C charge
located 1.5 m away?

Respuesta :

The magnitude of the force is F=1.68×10 ^20  N

Explanation:

Given data

q1 =1.5  10 ^6 q2=3.2 10^6   r=1.5

We have the formula

By the coulomb's law

F= K. q1 ×q2 / r²

The K value is given by    

8.99  10^9 Nm²/ c²

substitute the values we get,

F= ( 8.99×  10^9 Nm²/ c²) ×(1.5 ×10 ^6)×(3.2 ×10 ^6)/ (1.6 m² )

F=1.68×10 ^20  N

The magnitude of the force is F=1.68×10 ^20  N

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