Question

Consider what you know about the relative locations of the vertex and x-intercepts of the graph of a quadratic function. Describe in detail how the quadratic formula defines these points algebraically.

Answer 1

Hello,

the relative locations of the vertex is (a,b)
and x-intercepts is x₀

y=k(x-a)+b
and
0=k(x₀-a)+b==>k=-b/(x₀-a)

==>y=-b/(x₀-a)*(x-a)+b

Answer 2

The relative positions of the vertices are (a, b)

, and the x-intercept is x₀

y = k (x-a) + b and

0 = k (x₀-a) + b ==> k = -b /. (X₀-a)

==> y = -b / (x₀-a) * (x-a) + b

What is an example of a quadratic function?

The equation of a quadratic function is f (x) = ax2 + bx + c. Where a ≠ 0. Let's look at some examples of quadratic functions. f (x) = 2x2 + 4x-5; where a = 2, b = 4, c = -5. f (x) = 3x2-9; where a = 3, b = 0, c = -9.

What are the three quadratic functions?

There are three general forms of quadratic equations.

• canonical form: y = a x 2 + b x + c y = ax ^ 2 + bx + c y = ax2 + bx + c.
• Factored format: y = a (x − r 1) (x − r 2) y = a (x-r_1) (x-r_2) y = a (x − r1) (x − r2)
• vertices Format: y = a (x − h) 2 + k y = a (x − h) ^ 2 + k y = a (x − h) 2 + k.

Learn more about quadratic function here: https://brainly.com/question/1497716

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