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all the C ends up as CO2
mg of C = (12.011/44.011) x 33.5 mg CO2 = 9.142 mg C
all of the H ends up as H2)
mg H = (2.016/18.016) x 41.1 mg H2O = 4.599 mg H
mg N = 35.0 - 9.14 - 4.60 = 21.26
CxHyNz represents the empirical formula
where x = moles of C atoms, y = moles of H atoms, and z = moles of N atoms in (1 mole of) the molecule
Calculate the moles of C, H, and N that you found.
Determine the ratio of the moles x : y : z
Do that and then look at my calculations-
9.14 mg C / 12.011 mg/mmol = 0.76 millimol C
4.60 mg H / 1.008 mg/mmol = 4.60 millinol H
21.26 mg N / 14.006 mg/mmol = 1.52 millimol N
divide by the smallest number (0.76)
C = 1
H = 6
N = 2
all the C ends up as CO2
mg of C = (12.011/44.011) x 33.5 mg CO2 = 9.142 mg C
all of the H ends up as H2)
mg H = (2.016/18.016) x 41.1 mg H2O = 4.599 mg H
mg N = 35.0 - 9.14 - 4.60 = 21.26
CxHyNz represents the empirical formula
where x = moles of C atoms, y = moles of H atoms, and z = moles of N atoms in (1 mole of) the molecule
Calculate the moles of C, H, and N that you found.
Determine the ratio of the moles x : y : z
Do that and then look at my calculations-
9.14 mg C / 12.011 mg/mmol = 0.76 millimol C
4.60 mg H / 1.008 mg/mmol = 4.60 millinol H
21.26 mg N / 14.006 mg/mmol = 1.52 millimol N
divide by the smallest number (0.76)
C = 1
H = 6
N = 2
When the atoms of a chemical reaction are represented as the whole number ratio of atoms present then it is called the empirical formula.
C atom generally forms CO₂ and H atoms as H₂.
- mg of C atom can be calculated by:
[tex]\dfrac{12.011}{44.011} \times 33.5 \text{ mg CO{2} }[/tex]
= 9.142 mg C
- mg of H atom can be calculated by:
[tex]\dfrac{2.016}{18.016} \times 41.1 \text{ mg H{2}O}[/tex]
= 4.599 mg H
- Therefore, the mg of N atom in the compound will be:
= 35.0 - 9.14 - 4.60
= 21.26 mg N
The empirical formula can be represented as:
CxHyNz
where, x = moles of C atoms, y = moles of H atoms, and z = moles of N atoms
Moles of the atoms can be calculated:
- 9.14 mg C / 12.011 mg/mmol
= 0.76 millimol C
- 4.60 mg H / 1.008 mg/mmol
= 4.60 millimol H
- 21.26 mg N / 14.006 mg/mmol
= 1.52 millimol N
Now divide the moles calculated by the smallest number that is 0.76:
C = 1
H = 6
N = 2
So, the ratio of the moles x : y : z = 1:6:2
Therefore, the empirical formula and the compound will be:
CH₆N₂, methanediamine.
To learn more about empirical formulas follow the link:
https://brainly.com/question/14044066