first, we need to find side of square
[tex] {x}^{2} = 36 \\ x = 6[/tex]
36:3=12cm^2 - for 1 part
first rectangle has area of
12*2=24cm^2
secomd rectandle has area of
12*1=12cm^2
first side of rectangles is 6cm
second side of first rectangle:
[tex]6 \times x = 24 \\ x = 4[/tex]
second side of second rectangle:
[tex]6 \times x = 12 \\ x = 2[/tex]
Answer:
the dimensions of first rectangle: 4 and 6
the dimensions of second rectangle: 2 and 6
Answer:
Dimensions of:
Rectangle A are 6 cm by 4 cm.
Rectangles B are 6 cm by 2 cm.
Step-by-step explanation:
It is given that:
The area of square is 36 cm^2.
Hence, the side of the square is given as:
[tex]Area = (side)^{2}\\36 = (side)^{2} \\side = 6\\\\Hence, the side of square is 6 cm.Now, as the area of two rectangles A and B are in the ratio:2:1This means that, the area of rectangle A is 24 cm^2.and area of rectangle B is 12 cm^2.( Since, 36/(2+1)=36/3=12Area of rectangle A=2×12=24 cm^2.Area of rectangle B=1×12=12 cm^2. )Hence, the dimensions of A are:6 cm by 4 cm.and the dimensions of rectangle B are:6 cm by 2 cm.[/tex]
