Answer:
1) The resistance is 2 ohms.
2) The voltage is 4.95 V.
3) The current is 150 amps.
4) The resistance is 0.05 ohms.
Step-by-step explanation:
Using formula, [tex]\text{Resistance}=\frac{\text{Voltage}}{\text{Current}}[/tex]
1) A 12 V battery produces a current of 6 amps. What is the resistance ?
Voltage - 12 V and Current - 6 amps
[tex]\text{Resistance}=\frac{12}{6}[/tex]
[tex]\text{Resistance}=2[/tex]
The resistance is 2 ohms.
2) Silver has a resistance of 0.0198 ohms. What voltage would produce a current of 250 amps?
Resistance - 0.0198 ohms and Current - 250 amps
[tex]0.0198=\frac{\text{Voltage}}{250}[/tex]
[tex]\text{Voltage}=0.0198\times 250[/tex]
[tex]\text{Voltage}=4.95[/tex]
The voltage is 4.95 V.
3) What is the current produced by a potential dillerence of 120 volts through a resistance of 0.8 ohms?
Resistance - 0.8 ohms and Voltage - 120 V
[tex]0.8=\frac{120}{\text{Current}}[/tex]
[tex]\text{Current}=\frac{120}{0.8}[/tex]
[tex]\text{Current}=150[/tex]
The current is 150 amps.
4) What resistance would produce a current of 120 amps liom a 6 V battery"?
Voltage - 6 V and Current - 120 amps
[tex]\text{Resistance}=\frac{6}{120}[/tex]
[tex]\text{Resistance}=0.05[/tex]
The resistance is 0.05 ohms.
150A is produced by a potential difference of 120 volts through a resistance of 0.8 ohms
Given the formula:
E = IR;
where E is the voltage in Volts, I is the current in Ampere and R is the resistance in Ohms.
a) E = 12V, I = 6A, hence:
12 = 6R
R = 2 Ohms
b) R = 0.0198 Ohm, I = 250A, hence:
E = IR = 0.0198 * 250 = 4.95 V
c) E = 120V, R = 0.8 Ohm
120 = 0.8I
I = 150A
d) I = 120A, E = 6V
E= IR
6 = 120R
R = 0.05 Ohm
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