Respuesta :
Function 1 written in vertex form is f(x) = -x^2 + 8x - 15 = -(x^2 - 8x + 15) = -(x^2 - 8x + 16 + 15 - 16) = -(x - 4)^2 - (-1) = -(x - 4)^2 + 1
Therefore, vertex = (4, 1)
Function 2 written in vertex form is f(x) = -x^2 + 4x + 1 = -(x^2 - 4x - 1) = -(x^2 - 4x + 4 - 1 - 4) = -(x - 2)^2 - (-5) = -(x - 2)^2 + 5
Therefore vertex = (2, 5)
Function 1 has a maximum at y = 1 and function 2 has a maximum at y = 5. Therefore, function 2 has a larger maximum.
Therefore, vertex = (4, 1)
Function 2 written in vertex form is f(x) = -x^2 + 4x + 1 = -(x^2 - 4x - 1) = -(x^2 - 4x + 4 - 1 - 4) = -(x - 2)^2 - (-5) = -(x - 2)^2 + 5
Therefore vertex = (2, 5)
Function 1 has a maximum at y = 1 and function 2 has a maximum at y = 5. Therefore, function 2 has a larger maximum.
The function 2 represented by the equation f(x) = -(x - 2)² + 5 has the larger maximum
How to complete the blank spaces?
The functions are given as:
Function 1
f(x) = -(x - 4)² + 1
Function 2:
f(x) = -(x - 2)² + 5
A quadratic function is represented as:
f(x) = a(x - h)² + k
When a is negative then, the vertex of the function is a maximum
In both functions, the value of a is -1
This means that both functions are at a maximum
The values of k in both functions are:
Function 1: k = 1
Function 2: k = 5
By comparison. 5 is greater than 1
Hence, function 2 has the larger maximum
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