Respuesta :
The hypotenuse is given by
[tex] 3^{2} + 3^{2} =Hypotenuse squared 9+9= h^{2} h= \sqrt{18} [/tex]
Perimeter=(3+3+[tex] \sqrt{18} [/tex])feet
P=6+3[tex] \sqrt{2} ) feet[/tex]
[tex] 3^{2} + 3^{2} =Hypotenuse squared 9+9= h^{2} h= \sqrt{18} [/tex]
Perimeter=(3+3+[tex] \sqrt{18} [/tex])feet
P=6+3[tex] \sqrt{2} ) feet[/tex]
Answer:
Perimeter = 6+ [tex]3\sqrt{2}[/tex] ft
Step-by-step explanation:
Since given triangle is isosceles and right therefore two equals sides are the legs of right triangle given 3 and third side Hypotenuse say (x )
Using Pythagorean theorem , we get
[tex]x^{2} = 3^{2} +3^{2} \\ = 9 + 9 \\ = 18 \\x^2 = 18 \\[/tex]
taking square root both sides ,we get
[tex]x = 3\sqrt{2}[/tex]
Three sides of given triangles are
3 ft ,3ft and [tex]3\sqrt{2}[/tex]
Perimeter is given by = sum of all three sides = 3+3+ [tex]3\sqrt{2}[/tex]
= 6 + [tex]3\sqrt{2}[/tex] ft