Respuesta :
PH=-log[H⁺]
First solution:
PH=11.2
11.2=-log[H⁺]
log[H⁺]=-11.2
[H⁺]=10⁻¹¹.²=6.0309⁻¹²
Second solution:
PH=2.4
2.4=-log[H⁺]
log[H⁺]=-2.4
[H⁺]=10⁻².⁴=3.98*10⁻³
Difference between the two solutions=3.98*10⁻³ - 6.03*10⁻¹²≈4.0*10⁻³.
Answer: b) 4.0*10⁻³
First solution:
PH=11.2
11.2=-log[H⁺]
log[H⁺]=-11.2
[H⁺]=10⁻¹¹.²=6.0309⁻¹²
Second solution:
PH=2.4
2.4=-log[H⁺]
log[H⁺]=-2.4
[H⁺]=10⁻².⁴=3.98*10⁻³
Difference between the two solutions=3.98*10⁻³ - 6.03*10⁻¹²≈4.0*10⁻³.
Answer: b) 4.0*10⁻³
Answer:
The correct answer si option (b).
Explanation:
[tex] pH = -\log[H+][/tex]
Concentration of hydrogen ions when pH is 11.2.
[tex]11.2=-\log[H^+][/tex]
[tex][H^+]=6.309\times 10^{-12} M[/tex]
Concentration of hydrogen ions when pH is 12.4.
[tex]2.4=-\log[H^+][/tex]
[tex][H^+]'=0.0039810 M=3.9810\times 10^{-3} M[/tex]
Difference between the hydrogen ions:
[tex]=[H^+]'-[H^+][/tex]
[tex]=0.00398 M-6.309\times 10^{-12} M=0.00397 M=3.97\times 10^{-3}\approx 4.0\times 10^{-3}M[/tex]
Hence, the correct answer si option (b).