Question

Consider the balanced reaction bellow. How many moles of barium hydroxide,Ba(OH)2, would be required to react with 117g hydrogen bromide,2HBr+Ba(OH)2=BaBr2+2H2

Answer 1

Mol of HBr = mass/Mr = 117/(1+80) = 1.444 From equation, 2 moles hydrogen bromide reacts with 1 mole of barium hydroxide.... So 1.444 moles of hydrogen bromide react with (1.444/2) = 0.722 moles of barium hydroxide.