Question

The area of a rectangle is (see attachment) and the width is x+1 Find the length.

Answer 1

$x^2+2x+1=x^2+2x\cdot1+1^2=(x+1)^2=(x+1)(x+1)\\used:(a+b)^2=a^2+2ab+b^2\\\\A_{\fbox{ }}=wl\\\\w=x+1;\ l=?\\\\l(x+1)=x^2+2x+1\\l(x+1)=(x+1)(x+1)\\\\therefore\ l=x+1$