Question

find the equation of the line that has a slope of -3 and passes through (4, 4)

Answer 1

$The\ slope-point\ form:y-y_1=m(x-x_1)\\The\ slope-intercept\ form:y=mx+b\\--------------------\\m=-3;\ (4;\ 4)\to x_1=4\ and\ y_1=4\\\\\boxed{y-4=-3(x-4)}\\\\y-4=-3x+12\ \ \ |add\ 4\ to\ both\ sides\\\boxed{y=-3x+16}$