Respuesta :
Hello,
6x²+2x-20=0
==>6x²+12x-10x-20=0
==>6x(x+2)-10(x+2)=0
==>(x+2)(6x-10)=0
==>x=-2 or x=5/3
6x²+2x-20=0
==>6x²+12x-10x-20=0
==>6x(x+2)-10(x+2)=0
==>(x+2)(6x-10)=0
==>x=-2 or x=5/3
Answer:
[tex]x=\frac{5}{3}[/tex] and [tex]x=-2[/tex]
Step-by-step explanation:
The given equation is:
[tex]6x^2+2x-20=0[/tex]
which can be simplified as:
[tex]3x^2+x-10=0[/tex]
Factorizing the above equation, we get
[tex]3x^2+6x-5x-10=0[/tex]
[tex]3x(x+2)-5(x+2)=0[/tex]
[tex](3x-5)(x+2)=0[/tex]
Thus, Using the zero product property ,the solutions of the given equations are:
[tex]x=\frac{5}{3}[/tex] and [tex]x=-2[/tex]