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caylus
Hello,

6x²+2x-20=0
==>6x²+12x-10x-20=0
==>6x(x+2)-10(x+2)=0
==>(x+2)(6x-10)=0

==>x=-2 or x=5/3

Answer:

[tex]x=\frac{5}{3}[/tex] and [tex]x=-2[/tex]

Step-by-step explanation:

The given equation is:

[tex]6x^2+2x-20=0[/tex]

which can be simplified as:

[tex]3x^2+x-10=0[/tex]

Factorizing the above equation, we get

[tex]3x^2+6x-5x-10=0[/tex]

[tex]3x(x+2)-5(x+2)=0[/tex]

[tex](3x-5)(x+2)=0[/tex]

Thus, Using the zero product property ,the solutions of the given equations are:

[tex]x=\frac{5}{3}[/tex] and [tex]x=-2[/tex]

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