Question

The graph represents function 1, and the equation represents function 2: A coordinate plane graph is shown. A horizontal line is graphed passing through the y-axis at y = 3. Function 2 y = 5x + 4 How much more is the rate of change of function 2 than the rate of change of function 1

Answer 1

function 1 : horizontal line....a horizontal line has a rate of change (slope) = 0
function 2: y = 5x + 4.....the rate of change (slope) in y = mx + b form, is in the m position...so the rate of change (slope) is 5.

function 2 is 5 greater then function 1.

Answer 2

The rate of change of a function is its slope

The rate of change of function 2 is 5 greater than the rate of change of function 1

The equation of the graph of function 1 is:

$\mathbf{y =3}$

The equation of function 2 is:

$\mathbf{y =5x +4}$

A linear equation is represented as:

$\mathbf{y = mx + b}$

Where m represents the slope or the rate of change

By comparing $\mathbf{y = mx + b}$ to $\mathbf{y =3}$, the rate of change of the equation of function 1 is:

$\mathbf{m_1 = 0}$

By comparing $\mathbf{y = mx + b}$ to $\mathbf{y =5x +4}$, the rate of change of the equation of function 2 is:

$\mathbf{m_2 = 5}$

So, we have:

$\mathbf{m_1 = 0}$ --- function 1

$\mathbf{m_2 = 5}$ --- function 2

The difference in their rates is:

$\mathbf{d = m_2 - m_1}$

Substitute values for m2 and m1

$\mathbf{d = 5 - 0}$

$\mathbf{d = 5}$

Hence, the rate of change of function 2 is 5 greater than the rate of change of function 1

Read more about rates of change at:

https://brainly.com/question/13103052