Question

factor the expression. 20x^2 22x – 12

a. 2(5x 4)(2x – 3)

b. (10x – 2)(4x 3)

c. 2(5x – 2)(2x 3)

d. 2(5x 2)(2x – 3)

Answer 1

If you would like to factor the expression 20x^2 + 22x - 12, you can do this using the following steps:

20x^2 + 22x - 12 = 2 * (10x^2 + 11x - 6) = 2 * (5x - 2) * (2x + 3)

The correct result would be c. 2 * (5x - 2) * (2x + 3).

Answer 2

20x^2+22x-12
2 (10x^2+11x-6)
2 (10x^2+15x-4x-12)
2 (5×(2x+3)-2 (2x+3)
2 (2x+3)(5x-2) answer is c