A quantity b varies jointly with c and d and inversely with e. When b is 18, c is 4, d is 9, and e is 6. What is the constant of variation?

1/12
1/3
3
12

Respuesta :

b[tex] \alpha [/tex][tex] \frac{cd}{e} [/tex]
b=[tex]k \frac{cd}{e} [/tex]
Where k is a constant of proportionality.
b=18, c=4,d=9, e=6
Finding the value f k,
18=[tex] \frac{k*4*9}{6} [/tex]
6k=18
k=3
The equation then is;
b=[tex] \frac{3cd}{e} [/tex]
The constant of variation=3

Answer:

The answer is C. 3

Step-by-step explanation:

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