Answer:
Correct answer: V = 118.83 m/s
Explanation:
Given:
m = 450 g = 0.45 kg mass of the object
H = 706 m the height of the cliff from which the object was dropped
V = ? final velocity before object impact the ground
This movement is a free fall.
The velocity is calculated using the following formula:
V² = 2 · g · H in calculating we will use g = 10 m/s²
V² = 2 · 10 · 706 = 14,120 ⇒ V = √14,120 = 118.83 m/s
V = 118.83 m/s
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