Question

How do I solve the question the width of a rectangle is six meters more less than it's length. If the area of the rectangle is 112m squared find the dimensions of the rectangle

Answer 1

Answer:

Length of rectangle = 14 meters

width of rectangle = 8 meters

Step-by-step explanation:

Let the length of rectangle be x meters

width of the triangle is (x - 6) meters

Area of the rectangle is Length x width

112m² = x * (x -6)

112 = x² - 6x

x² - 6x - 112 = 0

x² - 14x +  8x - 112 = 0

x (x - 14) + 8 ( x - 14) = 0

(x - 14)(x + 8) = 0

x - 14 = 0                                     x + 8 = 0

x = 14                                           x = -8

width can't be negative value

Therefore,

Length of rectangle = 14 meters

width of rectangle = 14 - 6 meters

                              = 8 meters

Answer 2

The dimensions of the rectangle is 14m by 8m

The formula for calculating the area of a rectangle is expressed as:

A = LW

L is the length

W is the width

If the width of a rectangle is six meters less than its length, then;

W = L - 6

Substitute into the expression

A = L(L-6)

112 = L^2 - 6L

L^2 - 6L - 112 = 0

On factorizing, the value of L is 14 and -8

Recall that W = L - 6

W = 14 - 6

W = 8

Hence the dimensions of the rectangle is 14m by 8m

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