Answer:
[tex]\frac{3}{12}, \frac{2}{12}, \frac{4}{12}[/tex]
[tex]\frac{1}{6} < \frac{3}{12} < \frac{1}{3}[/tex]
Step-by-step explanation:
We can write three-twelfth as :
[tex]\frac{3}{12}[/tex]
Now, we can write one-sixth as :
[tex]\frac{1}{6} = \frac{1 \times 2}{6 \times 2} = \frac{2}{12}[/tex]
And, we can write one third as :
[tex]\frac{1}{3} = \frac{1 \times 4}{3 \times 4} = \frac{4}{12}[/tex]
Now, since 2 < 3 < 4, then [tex]\frac{2}{12} < \frac{3}{12} < \frac{4}{12}[/tex]
⇒ [tex]\frac{1}{6} < \frac{3}{12} < \frac{1}{3}[/tex]
So, this is the ordered numbers from least to greatest. (Answer)