Respuesta :
12,15,20,23,28....median is 20
if u throw another 20 in there, the median will remain the same
if u throw another 20 in there, the median will remain the same
Answer:
Option C is correct.
Step-by-step explanation:
We have been given total 8 data
Data is : 12,15,18,20,23,23,28
Here, n=7
Median is [tex]\frac{n+1}{2}=\frac{7+1}{2}=4th term[/tex]
Median is 20.
When one data is added n=8
The median of even number of data is
[tex]median=\frac{\frac{n}{2}\text{th and}\frac{n}{2}+1\text{th}}{2}[/tex]
Median is [tex]\frac{8}{2}\text{th and}\frac{8}{2}+1th[/tex]
Median is [tex]4\text{th and}5th[/tex]
4th terms is 20
5th terms is 23
Since, median should not be change hence,
Median will be 20.
Therefore, option C is correct.