Question

A Pontiac Grand am I Pinterest so will Roger turn pike traveling at 50 mph. Once half an hour later a ford Mustangs enter the turnpike at the same location and travel in the same distance at 80 mph. How long would it take for the mustang to catch up to the grand am ?When it catch up how far will the two cars have traveled on the turnpike

Answer 1

Answer:

It will take 0.8333h for the mustang to catch up to the grand am.

The two cars will have traveled 66.664 miles on the turnpike

Step-by-step explanation:

The position for each car can be modeled by equations in the following format:

$S(t) = S(0) + vt$

In which S(t) is the position t hours after the last car(the Ford Mustang) has left, S(0) is the position of each car when the Ford Mustang left and v is the speed of each car, in miles per hour.

Pontiac

Traveling at 50 mph, which means that $v = 50$.

The Ford Mustang leaves half an hour after the Pontiac. The Pontiac travels at 50 mph, which means that in this interval, the Pontiac will have traveled 0.5*50 = 25 mph. This means that S(0) = 25. So

$S_{P}(t) = 25 + 50t$

Ford Mustang

Leaves from position 0, so S(0) = 0.

Travel in the same distance at 80 mph, so $v = 80$. So

$S_{M}(t) = 80t$

How long would it take for the mustang to catch up to the grand am ?

This is t when

$S_{M}(t) = S_{P}(t)$

$80t = 25 + 50t$

$30t = 25$

$t = \frac{25}{30}$

$t = 0.8333$

It will take 0.8333h for the mustang to catch up to the grand am.

When it catch up how far will the two cars have traveled on the turnpike

This is either $S_{M}(0.8333)$ or $S_{P}(0.8333)$, since they will be in the same position. So

$S_{M}(t) = 80t$

$S_{M}(0.8333) = 80*0.8333 = 66.664$

The two cars will have traveled 66.664 miles on the turnpike