Answer:
Therefore I would earn $532,761 more on the first investment than in the second investment.
Step-by-step explanation:
The formula of compound interest
[tex]A=P(1+r)^n[/tex]
Compound interest [tex]I=A-P[/tex]
A= Amount after n years
P= Principal
r=Rate of interest
n= Number of years
First investment,
P₁=$22,000, r=12%=0.12 and n=30 years
[tex]A_1= 22,000(1+0.12)^{30}[/tex]
=659,118.28
≈$659,118
[tex]I_1[/tex]= [tex]A_1[/tex]-P₁
=$(659,118-22,000)
=$637,118
Second investment,
P₂=$22,000, r=6%=0.06 and n=30 years
[tex]A_1= 22,000(1+0.06)^{30}[/tex]
=126,356.81
≈$126,357
[tex]I_2[/tex]= [tex]A_2[/tex]-P₂
=$(126,357-22,000)
=$104357
[tex]I_1-I_2[/tex]
=$(637,118-104,357)
=$532,761
Therefore I would earn $532,761 more on the first investment than in the second investment.