Answer:
See below.
Step-by-step explanation:
(a+bz)/(a+b)=(c+dz)/(d+c) if bc=ad
bc = ad gives a = bc/d.
Substituting for a on the left side of the first equation:
(bc/d + bz)(bc/d + b) = (bc + bdz) / d * d/ (bc + bd)
= (bc + bdz)(bc + bd)
But bc = ad so we have:
(ad + bdz) / (ad + bd) .................(A)
From bc = ad we get c = ad/b.
Substituting for c on the right side of the first equation:
(ad/b + bz)(d + ad/b) = (ad + bdz) / b * b / (bd + ad)
= (ad + bdz ) / ( ad + bd) which is equal to (A) above.
So the original identity is true.
Answer:
Allrealnumbers
Step-by-step explanation:
When bc=ad, you divide both sides by b and you get c=ad/b, you then substituite that into your equation to see that it works and bith sides equal each other, therefore, making it true for all real numbers.
