Question

At what temperature Kelvin would
4.00 mol H2 in a 100 L container
exert a pressure of 1.00 atm?

Answer 1

Answer:

The temperature would be 304, 87 K

Explanation:

We use the formula PV= nRT:

T= PV/nR = 1,00 atm x 100L /4,00 mol x 0,082 l atm/K mol=304, 87 K

Answer 2

The temperature would be 304, 87 K