Given:
Funnel is in the shape of a cone.
Radius = 4 inches
Height = 10 inches
To find:
a) The volume of the funnel
b) How many quarts of oil are in the funnel.
Solution:
Volume of cone:
[tex]$V=\frac{1}{3}\pi r^2 h[/tex]
[tex]$V=\frac{1}{3}\times 3.14 \times 4^2 \times 10[/tex]
[tex]$V=167.47[/tex] in³
The volume of the funnel is 167.47 in³.
1 qt ≈ 58 in³
To convert cubic inch to quarts divide by 58.
[tex]$167.47in^3=\frac{167.47}{58}[/tex]
= 2.9 quarts
Therefore 2.9 quarts of oil are in the funnel.