Answer:
The magnitude of change in momentum of the ball is [tex]97.5 m[/tex] and impulse is also [tex]97.5 m[/tex]
Explanation:
Given:
Velocity of a pitched ball [tex]v _{i} = 47[/tex] [tex]\frac{m}{s}[/tex]
Velocity of ball after impact [tex]v_{f} = -50.5[/tex] [tex]\frac{m}{s}[/tex]
From the formula of change in momentum,
[tex]\Delta P = m (v_{f} -v_{i} )[/tex]
Here mass is not given in question,
Mass of ball is [tex]m[/tex]
Change in momentum is given by,
[tex]\Delta P = m (-50.5 -47)[/tex]
[tex]\Delta P = -97.5 m[/tex]
Magnitude of change in momentum is
[tex]\Delta P = 97.5 m[/tex]
And impulse is given by
[tex]J = \Delta P[/tex]
[tex]J = -97.5 m[/tex]
So impulse and
Therefore, the magnitude of change in momentum of the ball is [tex]97.5 m[/tex] and impulse is also [tex]-97.5 m[/tex]