Question

A rock is thrown upward from a bridge into a river below. The function f(t) = −16???? 2 + 41t + 130 determines the height of the rock above the surface of the water (in feet) in terms of the number of seconds t since the rock was thrown.

Answer 1

Answer:

The bridge's height above the water is 130 feets.

Step-by-step explanation:

A rock is thrown upward from a bridge into a river below :

$h(t)=-16t^2+41t+130$

Here t is time in seconds

It is required to find the bridge's height above the water. When it reaches the height of the rock above the surface of the water, then :

h(t) = 0

$f(0)=-16t^2+41t+130\\\\f(0)=-16(0)^2+41(0))+130\\\\f(0)=130\ ft$

So, the bridge's height above the water is 130 feets.