Answer:
The answer is 40 mm^2 per mm
Step-by-step explanation:
The area of a square with side length is x
and
A(x) = [tex]x^2[/tex] ([tex]mm^2[/tex])
The Derivative of the area is the rate of change of the area.
so
[tex]A^{'[/tex](x) = 2x
and we have to find [tex]A^{'}[/tex](20)
so we put x = 20 in the derivative of the area we get
[tex]A^{'}[/tex](20) = 2(20)
[tex]A^{'}[/tex](20) = 40 [tex]mm^2[/tex] per mm
that is we need
A'(20) = 40 [tex]mm^2[/tex] per mm.