Question

The pupil of a cat's eye narrows to a vertical slit of width 0.540 mm in daylight. Assume the average wavelength of the light is 471 nm. What is the angular resolution for horizontally separated mice

Answer 1

Answer:

Resolution of the light will be equal to $872.22\times 10^{-6}radian$

Explanation:

We have given a pupil of cat  width of the slit d = 0.540 mm = $0.540\times 10^{-3}m$

Average wavelength of the light $\lambda =471nm=471\times 10^{-9}m$

We have to find the angular resolution for horizontally separated mice  

Angular resolution is given by $\Theta =\frac{\lambda }{d}=\frac{471\times 10^{-9}}{0.540\times 10^{-3}}=872.22\times 10^{-6}radian$

So resolution of the light will be equal to $872.22\times 10^{-6}radian$