Question

A cross-country skier is skiing along at a zippy 8.0 mis. She stops pushing and simply glides along, slowing to a reduced speed of 6.0 mis after gliding for 5.0 m. What is the magnitude of her acceleration as she slows

Answer 1

Answer:

$2.8 m/s^2$

Explanation:

We are given that

Initial speed,u=8 m/s

Final speed,v=6 m/s

Distance,s=5 m

We have to find the magnitude of her acceleration as she shows.

We know that

$v^2-u^2=2as$

Using the formula

$(6)^2-(8)^2=2a(5)=10a$

$-28=10a$

$a=\frac{-28}{10}=-2.8 m/s^2$

Magnitude of acceleration=$\mid a\mid=2.8 m/s^2$

Answer 2

Answer:

Acceleration, a = $2.8\ m/s^2$

Explanation:

Given that,

Initial speed of the skier, u = 8 m/s

Final speed of the skier, v = 6 m/s

Distance, d = 5 m

We need to find the magnitude of her acceleration. It is equal to the rate of change of speed. It is given by :

$v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{6^2-8^2}{2\times 5}\\\\a=-2.8\ m/s^2$

So, the magnitude of her acceleration is $2.8\ m/s^2$.