Question

The typical lifespan for various mammal species in captivity (L) in years has been related to averageadult size (M) in kilograms according to the regression equation seen below. A typical adult Meerkat weighs about 0.9 kilograms. What is the predicted lifespan of a Meerkat incaptivity, according to this equation? * 2 points 11.6 years 2.4 years 14.1 years 2.6 years 28.8 years

Answer 1

Complete Question:

The typical lifespan for various mammal species in captivity (L) in years has been related to average adult size (M) in kilograms according to the regression equation seen below.

$ln L = 2.468 + 0.2 (lnM)$

A typical adult Meerkat weighs about 0.9 kilograms. What is the predicted lifespan of a Meerkat incaptivity, according to this equation? * 2 points 11.6 years 2.4 years 14.1 years 2.6 years 28.8 years

Answer:

Option A) L = 11.6 years

Step-by-step explanation:

From the given equation:

$ln L = 2.468 + 0.2 (lnM)$..........(1)

Average adult size, M = 0.9 kg

Putting the value of M into the regression equation in (1)

$ln L = 2.468 + 0.2 (ln0.9)\\ln L = 2.468 + (-0.02107)\\ln L = 2.447\\L = e^{2.447} \\L = 11.55 years$

Answer 2

The question is an illustration of regressions.

The lifespan of a typical adult Meerkat that weighs about 0.9 kilograms is (a) 11.6 years

The regression equation is given as:

$\ln(L) = 2.468 + 0.2\ln(M)$

From the question, we have:

M = 0.9

Substitute 0.9 for M in $\ln(L) = 2.468 + 0.2\ln(M)$

$\ln(L) = 2.468 + 0.2\ln(0.9)$

Take natural logarithm of 0.9

$\ln(L) = 2.468 + 0.2\times -0.1054$

$\ln(L) = 2.468 -0.02108$

$\ln(L) = 2.44692$

Take exponents of both sides

$L = e^{2.44692}$

$L = 11.553$

Approximate

$L = 11.6$

Hence, the lifespan is (a) 11.6 years

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