Answer:
39.446L
Explanation:
since helium is ideal gas, we can use PV = nRT
P = pressure
V = volume
n = moles
R = gas constant
T = temperature in Kelvin
we are solving for V
V = [tex]\frac{nRT}{P}[/tex]
C to K temp transfer: K = C + 273, so K = 290 since C = 17
our gas constant is 0.08206 atm L/mol K, this gas constant r will change depending on what unit of pressure you are using (mmHg, atm, etc).
plug and chug
V = [tex]\frac{(2.3mol)(290K)(\frac{0.08206 atmL}{molK}) }{1 atm}[/tex]
canceling out units
V = [tex]\frac{2.3 * 209 * 0.08206L}{1}[/tex] = 39.446
