Question

Air was put into an automobile tire when the tire was cold, at 5.00 C. The tire’s air pressure was 3.04 atm. Later, the weather warms up. Also, the automobile is driven, further warming the tire. What will the tire’s pressure be when the temperature is 25.0 C?

Answer 1

Answer:

3.26 atm will the tire’s pressure be when the temperature is 25.0°C.

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and temperature of the gas.

We are given:

$P_1=3.04 atm\\T_1=5.00^oC=5.00+273 K=278.00 K\\P_2=?\\T_2=25^oC=25.0+273K=298.0K$

Putting values in above equation, we get:

$\frac{3.04 atm}{278.00 K}=\frac{P_2}{298.0 K}\\\\P_2=3.26 atm$

3.26 atm will the tire’s pressure be when the temperature is 25.0°C.