Answer:
Explanation:
a ) In this case A rests on B and both rest on horizontal surface
Both moves together .
Total reaction due to weight of both of them
R = 1.2 + 3.6 = 4.8 N
friction force by horizontal surface = μ R , μ is coefficient of friction .
= .3 x 4.8 = 1.44 N
Force equal to frictional force will be required to put both of them in uniform motion .
b ) If A is held stationary , friction force will arise at both , the upper and lower surface of B .
At upper surface friction force = μ x weight of A
= .3 x 1.2 = .36 N
At lower surface friction force = μ x weight of A +B
= .3 x 4.8
= 1.44
Total frictional force on B
= 1.8 N N .
So 1.8 N force will be required to put B in uniform keeping A stationary.