Answer:
z = 1.83<1.96
null hypothesis is accepted
The sample is came from a population mean
Step-by-step explanation:
Step :-1
The sample of 40 measured voltage amounts from a unit have a mean of 123.59 volts and a standard deviation of 0.31 volts
given sample size n =40
mean of the sample ×⁻ = 123.59 volts
standard deviation of sample σ = 0.31 volts
Step2:-
Null hypothesis :-
the sample is from a population with a mean equal to 120 volts.
H₀ : μ =120
Alternative hypothesis:-
H₁ : μ ≠120
level of significance:- α =0.05
Step 3:-
The test statistic
[tex]z = \frac{x_{-}-mean }{\frac{S.D}{\sqrt{n} } }[/tex]
substitute values and simplification
[tex]z = \frac{123.59-120}{\frac{0.31}{\sqrt{40} } }[/tex]
on simplification we get the calculated value
z = 1.83
The tabulated value z =1.96 at 0.05 % level of significance
Conclusion:-
Calculated Z < The tabulated value z =1.96 at 0.05 % level of significance
so the null hypothesis is accepted
The sample is came from a population mean