The first part of the question is missing and it says;
Electrons are made to flow through the copper strip of as shown in the attached image . The strip's cross section is 1.00 mm high and 30.5 mm wide, and the strip is placed in a magnetic field B = 4.00T
Answer:
Hall potential difference = 5.6 x 10^(-6) V
Explanation:
We are given that;
Thickness of copper strip; L = 1mm = 1 x 10^(-3)m
Width of copper strip; W = 30.5mm
Magnetic field; B = 4T
Current in the strip = 19A
Number density; n = 8.46 × 10²⁸ m⁻³
Formula for number density of charge is given by;
n = (B•I)/(V•L•e)
Where;
B is uniform Magnetic field
I is current
V is potential difference
L is thickness of strip
e is electron charge = 1.6 x 10^(-19)C
Thus, let's make V the subject;
V = (B•I)/(n•L•e)
V = (4 x 19)/(8.46 × 10²⁸•1 x 10^(-3)•1.6 x 10^(-19))
V = 76/(13.536 x 10^(6)) = 5.6 x 10^(-6) V
