Answer:
def sumSquares(num):
if (num == 0):
return 0
else:
return num*num + sumSquares(num-1)
print(sumSquares(7))
Explanation:
* The code is in Python
The function takes one parameter num. If the num is equal to 0, that means function checked all the numbers up until num, and stops.
If the num is not equal to 0, the function will calculate the square of the number. It multiplies the num with num, adds this multiplication to result of the same function with a parameter that is decreased by 1.
For example, if num is equal to 3 initially, following will happen:
first iteration: sumSquares(3) = 3x3 + sumSquares(2)
second iteration: sumSquares(2) = 2x2 + sumSquares(1)
third iteration: sumSquares(1) = 1x1 + sumSquares(0)
forth iteration : sumSquares(0) = 0
If you go from bottom to top,
We know that sumSquares(0) is equal to 0, that means the result of the third iteration is 1, 1 + 0
We know that sumSquares(1) is equal to 1, that means the result of the third iteration is 5, 4 + 1
We know that sumSquares(2) is equal to 5, that means the result of the third iteration is 14, 9 + 5
