Answer:
Mass = 32 g
Explanation:
Given data:
Mass of O₂ needed = ?
Mass of NH₃ react = 13.6 g
Solution:
Chemical equation:
4NH₃ + 5O₂ → 4NO + 6H₂O
Number of moles of ammonia:
Number of moles = mass/ molar mass
Number of moles = 13.6 g/ 17 g/mol
Number of moles = 0.8 mol
Now we will compare the moles of ammonia and oxygen from balance chemical equation.
NH₃ : O₂
4 : 5
0.8 : 5/4×0.8 = 1
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 1 mol × 32 g/mol
Mass = 32 g
