Answer:
0.0176m
Explanation:
Given that,
railroad track has a length of 40 m
temperature is T₁ −5 ◦C
temperature is T₂ 35 ◦C
linear expansion coefficient of steel is 11 × 10−6 ( ◦C)−1
Lo = 40 m
T₁ = -5° C
T₂ = 35° C
dT = T₂ - T₁
= 35 - (-5)
= 40°C
L = Lo*(1+alpha*dT)
dL = Lo*alpha*dT
dT = 40°C
alpah = 11 x 10⁻⁶
Lo = 40 m
dL = 40 × 11 x 10⁻⁶ × 40
= 0.0176m
Answer:
ΔL = 0.0176m
Explanation:
We are given;
Length of railroad track; L = 40 m
First Temperature; T1 = −5 ◦C
Second temperature; T2 = 35 ◦C
linear expansion coefficient of steel; α = 11 × 10^(−6) (◦C)^(-1)
The increase in length is given by the equation;
ΔL = α•L•ΔT
Where,
α is linear coefficient
L is length
ΔT is change in temperature.
ΔT = first temperature - Second Temperature
Thus, ΔT = 35 - (-5) = 35 + 5 = 40°C
Thus,plugging in relevant values,
ΔL = α•L•ΔT = 11 × 10^(−6)•40•40
ΔL = 0.0176m
