Question

Calculate the magnitude of the magnetic force on a 270 m length of wire stretched between two towers and carrying a 150 A current. The Earth's magnetic field of 4.0×10−5 T makes an angle of 80 ∘ with the wire

Answer 1

Answer:

Force on the wire is equal to 15.95 N    

Explanation:

We have given length of the wire l = 270 m

Current flowing in the wire i = 150 A

Magnetic field $B=4\times 10^{-5}T$

Angle between magnetic field and wire $\Theta =80^{\circ}$

We have to find the force on the wire

Force on current carrying conductor is equal to $F=IBlsin\Theta$

So $F=150\times 4\times 10^{-5}\times 270\times sin80^{\circ}=15.95N$

So force on the wire is equal to 15.95 N