Question

The figure is made up of a cylinder and a sphere which has been cut in half. The radius of each half sphere is 5 mm. What is
the volume of the composite figure? Use 3.14 for Round to the nearest hundredth.
5 mm
10 mm
Recall the formulas y-Bhand V-
376.80 cubic millimeters
847 80 cubic millimeters
1.177 50 cubic millimeters
1308 33 cubic millimeters

Answer 1

Answer:

Rounded to the nearest hundredth the volume of the composite figure is:

1308 33 cubic millimeters

Explanation:

Hello! I wrote the complete question in a comment above. The volume of a cylinder is defined as:

$V_{c}=\pi r^2 h \\ \\ r:radius \\ \\ h:height$

While the volume of half a sphere is:

$V_{hs}=\frac{2}{3}\pi r^3$

Since we have 2 half spheres, then the volume of these is the same as the volume of a sphere:

$V_{s}=\frac{4}{3}\pi r^3$

Then, the composite figure is:

$V=\pi r^2 h +\frac{4}{3}\pi r^3 \\ \\ V=\pi r^2(h+\frac{4}{3}r)$

The radius of the cylinder is the same of the radius of each half sphere. So:

$r=5mm \\ \\ h=10mm \\ \\ \\ V=(3.14) (5)^2((10)+\frac{4}{3}(5)) \\ \\ V=25(3.14)(10+\frac{20}{3}) \\ \\ \boxed{V\approx 1308.33mm^3}$