To estimate the average cost of flowers for summer weddings in a certain region, a journalist selected a random sample of 15 summer weddings that were held in the state. A graph of the sample data showed an approximately symmetric distribution with no outliers. The sample mean and standard deviation were $734 and $102, respectively. The journalist will create a 95 percent confidence interval to estimate the population mean. Have all conditions for inference been met?

A. Yes, all conditions have been met.

B. No, the 15 weddings in the sample were not selected at random.

C. No, the sample size is not large enough to assume the sampling distribution of sample means is approximately normal.

D. No, because the graphical display is approximately symmetric it cannot be assumed that the sampling distribution of sample means is approximately normal.

E. No, the sample size of 15 is not less than 10 percent of all weddings in the state.

Going between C and D.

Based on the information given, the correct option will be C. No, the sample size is not large enough to assume the sampling distribution of sample means is approximately normal.

Based on the information given, it was stated that in order to estimate the average cost of flowers for summer weddings in a certain region, a journalist selected a random sample of 15 summer weddings that were held in the state.

It should be noted that Z test is typically greater than 30 samples. In this case, the number of samples used is 15.

Therefore, the sample size is not large enough to assume the sampling distribution.

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